2c^2-1200=-525

Solution for 2c^2-1200=-525 equation:

2c^2-1200=-525

We move all terms to the left:

2c^2-1200-(-525)=0

We add all the numbers together, and all the variables

2c^2-675=0

a = 2; b = 0; c = -675;
Δ = b2-4ac
Δ = 02-4·2·(-675)
Δ = 5400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5400}=\sqrt{900*6}=\sqrt{900}*\sqrt{6}=30\sqrt{6}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{6}}{2*2}=\frac{0-30\sqrt{6}}{4}
=-\frac{30\sqrt{6}}{4}
=-\frac{15\sqrt{6}}{2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{6}}{2*2}=\frac{0+30\sqrt{6}}{4}
=\frac{30\sqrt{6}}{4}
=\frac{15\sqrt{6}}{2}
$